php 递归多层关联数组

给你个思路，你结合具体项目改进吧，如下：

<?php

/**

*?@author:?suifengtec?coolwp.com

*?@date:2015-05-03?00:59:15

*?@last?Modified?by:suifengtec?coolwp.com

*?@last?Modified?time:?2015-05-04?01:16:09

*/

function?coolwp_routes_to_array($_routes){

$routes?=?array();

foreach($_routes?as?$key=>$val){

if(is_array($val)){

$routes[$key]?=?$val;

}else{

$routes[$key]?=?$val;

}

}

return?$routes;?

}

function?coolwp_get_route_from_array(array?$array,?$path,?$default?=?null){

$delimiter?=?'/';

if?(empty($path))?

throw?new?Exception('路径为空?');

$path?=?trim($path,?$delimiter);

$value?=?$array;

$parts?=?explode($delimiter,?$path);

foreach?($parts?as?$part)?{

if?(isset($value[$part]))?{

$value?=?$value[$part];

}?else?{

return?$default;

}

}

return?$value;

}

/*你的json*/

$string?=?file_get_contents("test.json");

$_routes?=?new?RecursiveIteratorIterator(

new?RecursiveArrayIterator(json_decode($string,?TRUE)),

RecursiveIteratorIterator::SELF_FIRST

);

/*==========以下为测试内容============*/

/*

转换为数组

*/

$routes?=?coolwp_routes_to_array($_routes);

/*

获取具体的路由的值

*/

/*$movie_route?=?coolwp_get_route_from_array($routes?,'account/loginIndex.htm/movie');

//输出为:?电影

echo?$movie_route;

*/

print_r($routes);

祝愉快！